C语言程序设计教程（第三版）课后习题5.7 （C语言代码）

解题思路:





注意事项:





参考代码:

#include<stdio.h>

int main()

{

int num,indiv,ten,hundred,thousand,ten_thousand,place;

scanf("%d",&num);

if(num>9999)

place=5;

else if(num>999)

place=4;

else if(num>99)

place=3;

else if(num>9)

place=2;

else place=1;

printf("%d\n",place);

ten_thousand=num/10000;

thousand=(int)(num-ten_thousand*10000)/1000;

hundred=(int)(num-ten_thousand*10000-thousand*1000)/100;

ten=(int)(num-ten_thousand*10000-thousand*1000-hundred*100)/10;

indiv=(int)(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10);

switch(place){

case 5:printf ("%d %d %d %d %d\n",ten_thousand,thousand,hundred,ten,indiv);

  printf("%d%d%d%d%d\n",indiv,ten,hundred,thousand,ten_thousand) ;

  break;

   case 4:printf ("%d %d %d %d\n",thousand,hundred,ten,indiv);

  printf("%d%d%d%d%d\n",indiv,ten,hundred,thousand) ;

  break;

case 3:printf ("%d %d %d\n",hundred,ten,indiv);

  printf("%d%d%d\n",indiv,ten,hundred) ;

  break;

case 2:printf ("%d %d\n",ten,indiv);      

  printf("%d%d\n",indiv,ten) ;

  break;

  case 1:printf("%d\n",indiv);

  printf("%d\n",indiv) ;

  break;

}

return 0;

}