冶炼金属C++

解题思路:

注意事项:

参考代码:

#include<bits/stdc++.h>

using namespace std;

int main() {

long long int a[10005], b[10005], max_v=1000000000;

int n;

cin >> n;

for (int i = 0; i < n; i++) {

cin >> a[i] >> b[i];

int temp = a[i] / b[i];

if (temp < max_v) { max_v = temp; }

}

int min_v = max_v;

while (min_v > 0) {

int x= 1;

int temp =min_v- 1;

for (int i = 0; i < n; i++) {

if (a[i]/temp==b[i]) { continue; }

x = 2; break;

}

if (x == 2) { break; }

min_v = temp; 

}

cout << min_v<< ' ' << max_v << endl;

}