年龄与疾病的简单计算

解题思路:

注意事项:

参考代码:

#include<stdio.h>

int main() {

int N,h,c1=0,c2=0,c3=0,c4=0;

double m1,m2,m3,m4;

scanf("%d",&N);

int ch[N];

for(int n=0;n<N;n++){

scanf("%d",&h);

ch[n]=h;

}

for(int i=0;i<N;i++){

if(ch[i]<=18) c1++;

else if(ch[i]<=35) c2++;

else if(ch[i]<=60) c3++;

else c4++;

}

m1=(double)c1/N*100;

m2=(double)c2/N*100;

m3=(double)c3/N*100;

m4=(double)c4/N*100;

printf("%.2f%%\n%.2f%%\n%.2f%%\n%.2f%%",m1,m2,m3,m4);

return 0;

}