2849:石头剪刀布

解题思路:

注意事项:

参考代码:

#include<stdio.h>

int main()

{

int n;

scanf("%d",&n);

char player1[20],player2[20];

int i;

    for(i=0;i<n;i++)

    {

        scanf("%s %s",player1,player2);

        if(strcmp(player1,player2)==0)//双方出的相同

            printf("Tie\n");

        if(strcmp(player1,"Rock")==0&&strcmp(player2,"Scissors")==0)

            printf("Player1\n");

        if(strcmp(player1,"Rock")==0&&strcmp(player2,"Paper")==0)

            printf("Player2\n");

        if(strcmp(player1,"Scissors")==0&&strcmp(player2,"Paper")==0)

            printf("Player1\n");

        if(strcmp(player1,"Scissors")==0&&strcmp(player2,"Rock")==0)

            printf("Player2\n");

        if(strcmp(player1,"Paper")==0&&strcmp(player2,"Rock")==0)

            printf("Player1\n");

        if(strcmp(player1,"Paper")==0&&strcmp(player2,"Scissors")==0)

            printf("Player2\n");

    }

return 0;

}

方法二：只比较首字符

#include<stdio.h>

int main()

{

    int n ;

    scanf("%d",&n);

    getchar();

    char player1[20],player2[20];

    for (int i=0;i<n;i++)

    {

        scanf("%s%s",player1,player2);

        if(player1[0]==player2[0])

            printf("Tie\n");

        else if((player1[0]=='R'&&player2[0]=='S')||(player1[0]=='S'&&player2[0]=='P')||(player1[0]=='P'&&player2[0]=='R'))

            printf("Player1\n");

        else if((player1[0]=='R'&&player2[0]=='P')||(player1[0]=='S'&&player2[0]=='R')||(player1[0]=='P'&&player2[0]=='S'))

            printf("Player2\n");

    }

    return 0;

}