1010c语言代码

解题思路:

注意事项:

参考代码:

#include<stdio.h>

int main()

{

int i,j;

scanf("%d",&i);

if(i<=100000){

j=i*0.1;

}

else if(i>100000&&i<=200000){

j=100000*0.1+(i-100000)*0.075;

}

else if(i>200000&&i<=400000){

j=100000*0.1+100000*0.075+(i-200000)*0.05;

}

else if(i>400000&&i<=600000){

j=100000*0.1+100000*0.075+200000*0.05+(i-400000)*0.03;

}

else if(i>600000&&i<=1000000){

j=100000*0.1+100000*0.075+200000*0.05+200000*0.03+(i-600000)*0.015;

}

else if(i>1000000){

j=100000*0.1+100000*0.075+200000*0.05+200000*0.03+400000*0.015+(i-1000000)*0.01;

}

printf("%d\n",j);

return 0;

}