数字的处理与判断（不用字符数组的解法）

解题思路:

注意事项:

参考代码:

#include <stdio.h>

#include <stdlib.h>

/*

给出一个不多于5位的整数，要求 1、求出它是几位数 2、

分别输出每一位数字 3、按逆序输出各位数字，

例如原数为321,应输出123

*/

                    int main(){

                         int num,count=0,r=0,t1,t2;

                         //char s[6]; //注意结束符 

                         scanf("%d",&num);

                         //printf("%d",);

                         t2=num; 

                         while(t2!=0){ //先求逆序数和位数

                             t1=t2%10;

                             r=r*10+t1;

                             t2/=10;

                             count++;

                         }

                        //再做输出

                         printf("%d\n",count);                        

                         t1=r;

                         while(t1!=0){

                             count--;

                             t2=t1%10;

                             t1/=10;

                             printf("%d",t2);

                             if(count>0)

                             putchar(' ');

                         }

                         putchar('\n');

                         printf("%d\n",r);

                         return 0;

                    }