c语言代码解决问题

解题思路:

注意事项:

参考代码:

#include<stdio.h>

#include<stdlib.h>

#include<math.h>

int main()

{

    int n,i;

    scanf("%d", &n);

    double* a,min,max,average=0,max_error=0;

    a = (double*)malloc(sizeof(double) * n);

    for (i = 0; i < n; i++)

        scanf("%lf", &a[i]);

    max = a[0], min = a[0];

    for (i = 1; i < n; i++)

    {

        if (min > a[i])

            min = a[i];

        if (max < a[i])

            max = a[i];

    }

    for (i = 0; i < n; i++)

    {

        if (a[i] != min && a[i] != max)

        {

            average += a[i];

        }

    }

    average=average/(double)(n-2);

    max_error =0;

    for (i = 0; i < n; i++)

    {

        if (a[i] != max && a[i] != min)

        {

            if (fabs(a[i] - average) > max_error)

            {

                max_error = fabs(a[i] - average);

            }

        }

    }

    printf("%.2lf %.2lf", average, max_error);

    return 0;

}