日期换算。。

解题思路:

注意事项:

参考代码:

#include<iostream>

using namespace std;

int main()

{

    int a,b;

    cin>>a>>b;

    switch(a)

    {

        case 1:

        cout<<b<<endl; break;

        case 2:

        cout<<b+31<<endl; break;

        case 3:

        cout<<b+31+28<<endl; break;

        case 4:

        cout<<b+31*2+28<<endl; break;

        case 5:

        cout<<b+31*2+28+30<<endl; break;

        case 6:

        cout<<b+31*3+28+30<<endl; break;

        case 7:

        cout<<b+31*3+28+30*2<<endl; break;

        case 8:

        cout<<b+31*4+28+30*2<<endl; break;

        case 9:

        cout<<b+31*5+28+30*2<<endl; break;

        case 10:

        cout<<b+31*5+28+30*3<<endl; break;

        case 11:

        cout<<b+31*6+28+30*3<<endl; break;

        case 12:

        cout<<b+31*6+28+30*4<<endl; break;

    }

    return 0;

}