10行代码完成--通俗易懂

解题思路:

注意事项:

参考代码:

#include<iostream>

using namespace std;

int main()

{   

    // 2020为庚子，根据2020重新排序天干地支，使a[0]="geng",b[4]="zi"，

    // 将年数除以60取余后，再分别除以10取余，进入天干数组获取天干

    // 将数除以12取余，进入地支数组获取地支

    // 最后将两个值顺序输出

    // 定义年份

    int y;

    // 天干

    string a[10]={"geng","xin","ren","gui","jia","yi","bing","ding","wu","ji"};

    // 地支

    string b[12]={"shen","you","xu","hai","zi","chou","yin","mao","chen","si","wu","wei"};

    cin>>y;

    // 将年份除以60取余

    int z=y%60;

    cout<<a[z%10]<<b[z%12]<<endl;

    return 0;

}