循环题解矩形的福利

解题思路:

注意事项:

参考代码:

#include<bits/stdc++.h>

using namespace std; 

int main() 

{ 

    int i,j; 

    int t,a=0,b=1,n,m=0,c[99345]={};

    while(cin>>n>>m)

    {

        if(n==0&&m==0) break;

            for(i=1;i<=n-1;i++)

            {

                cout<<" ";

            }

            for(i=1;i<=m;i++)

            {

                cout<<".";

            }

           cout<<endl;

            for(i=n-2;i>=1;i--)

            {

                for(j=1;j<=i;j++)

                {

                    cout<<" ";

                }

                cout<<".";

                for(j=1;j<=m-2;j++)

                {

                        cout<<" ";

                }

            cout<<".";

            cout<<endl;

            }

        for(i=1;i<=m;i++)

        {

        cout<<".";

        }

        for(i=1;i<=n-1;i++)

        {

        cout<<" ";

        }

        cout<<endl<<endl;

    }

return 0;

}