亲和数简单明了的题解

解题思路:编写一个函数便于解题

注意事项:

参考代码:

#include<iostream>

using namespace std;

int Sum(int k)

{

int sum = 0;

for (int j = 1; j <= (k/2); j++)

{

if (k % j == 0) { sum += j; }

}

return sum;

}

int main()

{

int N, a, b;

cin >> N;

for (int i = 0; i < N; i++)

{

cin >> a >> b;

if (Sum(a) == b && Sum(b) == a) { cout << "YES" << endl; }

else { cout << "NO" << endl; }

}

return 0;

}