蓝桥杯2018年第九届真题-等腰三角形

解题思路:

注意事项:

参考代码:

n=int(input())

s=''

for i in range(1,1000):

    s+=str(i)

l=[['.'for j in range(i+n)] for i in range(n)]

a1=s[:n]

a2=s[n:3*n-2]

a3=s[3*n-2:4*n-4][::-1]

for i in range(n):

    l[i][n-i-1]=a1[i]

for i in range(1,2*n-1):

    l[n-1][i]=a2[i-1]

for i in range(1,n-1):

    l[i][n+i-1]=a3[i-1]

for i in range(n):

    print(''.join(l[i]))