C++代码宏定义闰年判断

解题思路:
四年一闰；百年不闰，四百年再闰

if ((y%4==0) and (y%100!=0) or (y%400==0)) cout<<'L'<<endl;

else cout<<'N'<<endl;

注意事项:
暂时不明
参考代码:

#include<iostream>

using namespace std;

#define LEAP_YEAR(y) {if ((y%4==0) and (y%100!=0) or (y%400==0)) cout<<'L'<<endl;else cout<<'N'<<endl;}

int main()

{

    int y;

    cin>>y;

    LEAP_YEAR(y);

    return 0;

}