[编程入门]利润计算 C语言题解

解题思路:无脑ifelse

注意事项:

参考代码:

#include<stdio.h>

int main()

{

    int prize,profit;

    scanf("%d",&profit);

    if(profit <= 100000){

        prize = 0.1 * profit;

    }else if(profit > 100000 && profit <= 200000){

        prize = 100000 * 0.1 + (profit - 100000) * 0.075;

    }else if(200000<profit&&profit<=400000){

        prize = 100000 * 0.1 + (200000-100000) * 0.075 + (profit - 200000)*0.05;

    }else if(400000<profit&&profit<=600000){

        prize = 100000 * 0.1 + (200000-100000) * 0.075 + (400000-200000) * 0.05 + (profit - 400000) * 0.03;

    }else if(600000<profit&&profit<=1000000){

        prize = 100000 * 0.1 + (200000-100000) * 0.075 + (400000-200000) * 0.05 + (600000 - 400000) * 0.03 + (profit-600000)*0.015;

    }else if(profit>1000000){

        prize = 100000 * 0.1 + (200000-100000) * 0.075 + (400000-200000) * 0.05 + (600000 - 400000) * 0.03 + (1000000-600000)*0.015 + (profit-1000000)*0.01;

    }

    printf("%d",prize);

    return 0;

}