1010: [编程入门]利润计算

解题思路:

注意事项:

参考代码:

#include<stdio.h>

int main(void){

float i,sum=0;

scanf("%f",&i);

if(i>1000000)

sum=0.01*(i-1000000)+0.015*400000+0.03*200000+0.05*200000+0.075*100000+0.1*100000;

else if(i>600000&&i<=1000000)

sum=0.015*(i-600000)+0.03*200000+0.05*200000+0.075*100000+0.1*100000;

else if(i>400000&&i<=600000)

sum=0.03*(i-400000)+0.05*200000+0.075*100000+0.1*100000;

else if(i>200000&&i<=400000)

sum=0.05*(i-200000)+0.075*100000+0.1*100000;

else if(i>100000&&i<=200000)

sum=0.075*(i-100000)+0.1*100000;

else if(i>0&&i<=100000)

sum=0.1*i;

printf("%.0f\n",sum);

return 0;

}