解题思路:直接强制转换log2的返回值
注意事项:
参考代码:#include<iostream>
#include<cmath>
using namespace std;
#define MAXM 110
int main()
{
int n, m, i, x, y, sum;
int a[MAXM];
cin>>n>>m;
for(i = 1; i <= n; i++){
cin>>a[i];
}
while(m--)
{
sum = 0;
cin>>x>>y;
for(i = x; i <= y; i++){
a[i] = (int)log2(a[i]) + 1;
// cout<<a[i]<<endl;
}
for(i = 1; i <= n; i++){
sum += a[i];
}
cout<<sum<<endl;
}
}
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