用个字符串数组来装载所有的字符串就好了 注意输出的时候 先输出十位数 再输出个位数 写起来有点恶心。。。
#include<iostream> using namespace std; int main() { int h,m; char a[30][20]={{"zero"},{"one"},{"two"},{"three"},{"four"},{"five"},{"six"},{"seven"}, {"eight"},{"nine"},{"ten"},{"eleven"},{"twelve"},{"thirteen"},{"fourteen"},{"fifteen"},{"fifteen"},{"seventeen"}, {"eighteen"},{"nineteen"},{"twenty"},{"thirty"},{"forty"},{"fifty"}}; while(cin>>h>>m) { if(m!=0) { if(h>=20) { int h1=h/20; int h2=h%10; cout<<a[h1+19]<<" "; if(h2!=0) cout<<a[h2]<<" "; } else { cout<<a[h]<<" "; } if(m>=20) { int m1=m/10; int m2=m%10; cout<<a[m1+18]<<" "; if(m2!=0) cout<<a[m2]; } else { cout<<a[m]; } cout<<endl; } else { if(h>=20) { int h1=h/20; int h2=h%10; cout<<a[h1+19]<<" "; if(h2!=0) cout<<a[h2]<<" "; cout<<"o'clock"<<endl; } else cout<<a[h]<<" "<<"o'clock"<<endl; } } return 0; }
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