解题思路:
我的方法有点冗长(尴尬一笑)
注意事项:
参考代码:
#include<stdio.h>
#include<math.h>
int judge(int);
int main(void)
{
int num;
int i;
int array[5];
//printf("请输入一个不多于五位的数:\n");
scanf("%d",&num);
printf("%d\n",judge(num));
switch(judge(num))//根据位数输出
{
case 1:
printf("%d",num);
break;
case 2:
printf("%d %d",num/10,num%10);
break;
case 3:
printf("%d %d %d",num/10/10,num/10%10,num%10);
break;
case 4:
printf("%d %d %d %d",num/10/10/10,num/10/10%10,num/10%10,num%10);
break;
case 5:
printf("%d %d %d %d %d",num/10/10/10/10,num/10/10/10%10,num/10/10%10,num/10%10,num%10);
break;
}
switch(judge(num))
{
case 1:
printf("%d",num);
break;
case 2:
printf("\n%d%d",num%10,num/10);
break;
case 3:
printf("\n%d%d%d",num%10,num/10%10,num/10/10);
break;
case 4:
printf("\n%d%d%d%d",num%10,num/10%10,num/10/10%10,num/10/10/10);
break;
case 5:
printf("\n%d%d%d%d%d",num%10,num/10%10,num/10/10%10,num/10/10/10%10,num/10/10/10/10);
break;
}
}
int judge(int num)//判断位数
{
int count=0;
int i;
for(i=0;;i++)
{
//count++;
num=num/10;
count++;
if(num==0)
break;
}
return count;
}
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