结构体之时间设计

解题思路:

注意事项:

参考代码:

def leap(year):
   if (year % 4 == 0 and year % 100 != 0) or year % 400 == 0:
       return 1
   else:
       return 0


month_data = (
   (31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31),
   (31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31)
)
year, month, day = map(int, input().split())
days = day
for i in range(month - 1):
   days += month_data[leap(year)][i]
print(days)