题解列表

摘要：```c # include int main(void){ int a,n; scanf("%d %d",&a,&n); int sum=0,sum1=0; ……

摘要：```c #include int main(void){ double sum; double i=1; int j=1; do{ ……

摘要：```c # include long long fibo(int n); int main(void){ long long sum=0; int n; scan……

摘要：```cpp #include using namespace std; int main() { int sum1; sum1 = 0; int num1, num2; c……

摘要：```c # include int fibo(int N); int main(void){ int N; scanf("%d",&N); fibo(N); ……

摘要：```c # include # include int main(void){ char a[100]; gets(a); int sum=0; for……

摘要：/* 通过演绎推理 可以得出规律 1*1*1=1=1 2*2*2=8=3+5 3*3*3=27=7+9+11 4*4*4=64=13+15+17+19 5*5*5=125=21+23+25……

摘要：```c # include # include int main(void){ char a[50]; gets(a); for (int i=0;i=0;i--……

摘要：解题思路:注意事项:参考代码:import java.util.Scanner;public class C1687{ public static void main(String[] args){ ……

摘要：解题思路:注意事项:参考代码:import java.util.Scanner;public class C1688{ public static void main(String[] args){ ……