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【偶数求和】思路简单 代码精简 通俗易懂 hiahiahiahia

#思路很简单:1.将数列2,4,6,8,10...(100个)提前装进数组2.获取n,m3.遍历数组前n个元素,每m个相加求均值则输出4.最后判断n%m是否为0,若不为0表示最后还少输出一个,其个数有n%m个#include#includeusingnamespacestd;intmain(){int

Kanna-平均值计算(C语言代码)

不多说直接上代码:#includeintmain(){inta[10];intsum=0;floatave=0;for(inti=0;i<10;i++){scanf("%d",&a[i]);sum+=a[i];}ave=sum/10.0;sum=0;//sum归0计算大于平均值的数for(intj=0

超级楼梯-题解(C语言代码)

```c#includeunsignedlonglongintff(intm){if(m==1||m==0)return1;returnff(m-2)+ff(m-1);}intmain(){intn,m;scanf("%d",&n);while(n){n--;scanf("%d",

幸运儿-题解(C语言代码)

```c#include#include#include#include#includeusingnamespacestd;intmain(){intn;intremainNum;inta[56];intk=0;while(scanf("%d",&n)!=EOF){for(inti=0;i

C语言训练-8除不尽的数-题解(C++代码)

多层判断寻找自然数因为就一个找到就跳出循环避免死循环次运算```cpp#includeusingnamespacestd;intmain(){for(inti_for1_int=1;i_for1_int>0;i_for1_int++){inta_int=0;intb_int=0;if(i_for1_i