解题思路:
注意事项:
参考代码:
def yizi(d): s=0 for i in range(1,d//2+1): if d%i==0: s += i return s z = 0 for i in range(3,3000): if i == z: continue l=[] if yizi(yizi(i))==i and i != yizi(i): z = yizi(i) l=[i,yizi(i)] l.sort() print(f"({l[0]},{l[1]})",end='')
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