解题思路:
方法①:
switch(choise_F(A)) { case 1:{printf("%d\n\n",x+y);break;} case 2:{printf("%d\n\n",x-y);break;} case 3:{printf("%d\n\n",x*y);break;} case 4:{printf("%d\n\n",x/y);break;} case 5:{printf("%d\n\n",x%y);break;} case 6:break; } 此方法进行字符串的比较时比较实用
方法②:
switch(A) { case '+':{printf("%d\n\n",x+y);break;} case '-':{printf("%d\n\n",x-y);break;} case '*':{printf("%d\n\n",x*y);break;} case '/':{printf("%d\n\n",x/y);break;} case '%':{printf("%d\n\n",x%y);break;} default:break; }
注意事项:
输出结果后还要空一行
参考代码:
#include<stdio.h> int choise_F(char A); int main() { int x,y; char A; while(scanf("%d %d ",&x,&y)!=EOF) { scanf("%c",&A); switch(choise_F(A)) { case 1:{printf("%d\n\n",x+y);break;} case 2:{printf("%d\n\n",x-y);break;} case 3:{printf("%d\n\n",x*y);break;} case 4:{printf("%d\n\n",x/y);break;} case 5:{printf("%d\n\n",x%y);break;} case 6:break; } } return 0; } /*-------------------------------------------------*/ int choise_F(char A) { if(A=='+') return 1; else if(A=='-') return 2; else if(A=='*') return 3; else if(A=='/') return 4; else if(A=='%') return 5; else return 6; }
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