解题思路:现将整数化成二进制存储,做一个循环,再将二进制化成十进制(注释为调试代码)
注意事项:
参考代码:
#include <stdio.h>
int main()
{
unsigned int a,s = 0,t =1;
int i = 31;,n,j,b[100] = {0};
scanf("%u%u",&a,&n);
while(a)
{
b[i--] = a%2;
a /= 2;
}
/*for(i = 0;i < 32;++i)
printf("%d ",b[i]);
printf("\n");*/
for(j = 31+n;j>=n;--j)
b[j] = b[j-n];
for(i = 0;i < n;++i)
b[i] = b[32+i];
for(i = 31;i>=0;--i)
{
//printf("%d ",b[i]);
s += b[i]*t;
t *= 2;
}
//printf("\n");
printf("%d",s);
}
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