金币(仅供参考)

解题思路:

注意事项:

参考代码:

#include<stdio.h>

#include<math.h>

int main()

{

int n;

int sum=0;

scanf("%d", &n);

int num;

int i=1;

while (1)

{

num = i * (i + 1) / 2;

if (num < n)

i++;

else

break;

}

for (int j = 1; j <= i-1; j++)

{

for (int k = 1; k <= j; k++)

{

sum += j;

}

}

int variable = n - i * (i - 1) / 2;

sum += variable * i;

printf("%d", sum);

return 0;

}