#问题:分解n (大)-----分解n的二进制(小)
def rec(n):
for x in range(14,-1,-1):
s=n-pow(2,x)
if s>0:
if x==2:
print("2(2)+",end='')
elif x==1:
print("2+",end='')
elif x==0:
print("2(0)+",end='')
else:
print("2(",end='')
rec(x)
print(")+",end='')
n=s
if s==0:
if x==1:
print("2",end='')
return
elif x==0:
print("2(0)",end='')
return
else :
print("2(",end='')
rec(x)
print(")",end='')
return
n=int(input())
rec(n)
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