解题思路:
注意事项:
参考代码:
#include<stdio.h>
#include<stdlib.h>
int huffuman(int* a, int n)
{
int i, m1 = 1000001, m2 = 100001, x1 = -1, x2 = -1, l = n, sum = 0;
while (1)
{
for (i = 0; i < n; i++)
{
if (m1 > a[i] && a[i] > 0)
{
m2 = m1;
x2 = x1;
m1 = a[i];
x1 = i;
}
else if (m2 > a[i] && a[i] > 0)
{
m2 = a[i];
x2 = i;
}
}
a[x1] = m1 + m2;
sum += m1 + m2;
a[x2] = -1;
m1 = 100001;
m2 = 100001;
l--;
if (l == 1)
break;
}
return sum;
}
int main()
{
int n,*a, x, i;
scanf("%d", &n);
a = (int*)malloc(sizeof(int)*n);
if (a == NULL)
return 0;
for (i = 0; i < n; i++)
scanf("%d", &a[i]);
x = huffuman(a, n);
printf("%d", x);
return 0;
}
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