[编程入门]求和训练（一次循环实现）[C语言代码]

解题思路:

                思路：for循环的条件判断这里，可以很好的利用下，for(double i=1;    i<=a||i<=b||i<=c;     i++)   逻辑或判断可以让i小于最大输入值，

                然后每个输入值分别计算各自的和，用一个sum分别算和即可。
注意事项:

参考代码:

                                #include

                                /*

                                 求以下三数的和,保留2位小数 1~a之和 1~b的平方和 1~c的倒数和

                                */

                                int main(){

                                             double a,b,c;

                                             double sum=0;

                                             scanf("%lf %lf %lf",&a,&b,&c);

                                             for(double i=1; i<=a||i<=b||i<=c; i++){

                                                     if(a>=i){

                                                             sum+=i;

                                                     }

                                                     if(b>=i){

                                                              sum+=i*i;

                                                     }

                                                     if(c>=i){

                                                             sum+=1/i;

                                                     }

                                             }

                                             printf("%.2f",sum);

                                             return 0;

                                }