解题思路:
注意事项:
参考代码:
#include<stdio.h>
int main(){
int n, num, a[5], count;
scanf("%d",&n);
if (n < 10) count = 1;
else if (n<100 && n>9) count =2;
else if (n<1000 && n>99) count = 3;
else if (n<10000 && n>999) count = 4;
else if (n<100000 && n>9999) count = 5;
printf("%d\n",count);
for (int i = count - 1; i >= 0 ; i--){
a[i] = n % 10;
n /= 10;
}
for (int j = 0; j < count; j++){
printf("%-2d",a[j]);
}
printf("\n");
for (int k = count - 1; k >= 0; k--){
printf("%d",a[k]);
}
return 0;
}
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