一种超简单的方法 [编程入门]结构体之时间设计

解题思路:

注意事项:

参考代码:

#include<stdio.h>

struct date

{

    int year;

    int month;

    int day;

};

int main()

{

struct date today;

scanf("%d %d %d",&today.year,&today.month,&today.day);

int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};

int sum=0;

if(today.year%4==0&&today.year%100!=0||today.year%400==0)

a[1]=29;

for(int i=0;i<today.month-1;i++)

{

    sum+=a[i];

}

sum+=today.day;

printf("%d",sum);

return 0;

}