C语言 自定义函数&

解题思路:

注意事项:

参考代码:

#include <stdio.h>

#include <math.h>

#define LONG 10

int main()

{

         double fact(int n);

         double mypow(double x, int n);

         double x,S=0; int  n;

         scanf("%lf %d", &x, &n);

         for (int i = 1; i <= n; i++)

                  S =S+ mypow(-1, i-1)*mypow(x,i) / fact(i);

         printf("%.4lf", S);

         return 0;

}

double fact(int n)

{

         double count = 1;

         while (n != 0)

         {

                 count = count * n;

                 n--;

         }

         return count;

}

double mypow(double x, int n)

{

         double count=1;

         while (n != 0)

         {

                 count = count * x;

                 n--;

         }

         return count;

}