题解1010：利润计算

解题思路:使用递归实现

注意事项:

参考代码:

n=int(input())
def func(n):
    if n<=100000:
        result=n*0.1
    elif 100000<n<=200000:
        result=func(100000)+(n-100000)*0.075
    elif 200000<n<=400000:
        result=func(200000)+(n-200000)*0.05
    elif 400000<n<=600000:
        result=func(400000)+(n-400000)*0.03
    elif  600000<n<=1000000:
        result=func(600000)+(n-600000)*0.015
    else:
        result=func(1000000)+(n-1000000)*0.01
    return result
print(int(func(n)))