解题思路:
通过设置小时与分钟输出两函数来实现
注意事项:
注意中英文字符,大于20的数字输出
参考代码:
h,m=[int(i) for i in input().split()]
readline = {'0':'zero','1':'one','2':'two','3':'three','4':'four','5':'five',
'6':'six','7':'seven','8':'eight','9':'nine','10':'ten','11':'eleven','12':'twelve',
'13':'thirteen','14':'fourteen','15':'fifteen','16':'sixteen','17':'seventeen',
'18':'eighteen','19':'nineteen','20':'twenty','30':'thirty','40':'forty','50':'fifty'}
def clockread(h):
if h<=20:
print(readline[str(h)],end='')
else:
a=readline['20']
h=h-20
print(a,readline[str(h)],end='')
def minread(m):
if m==0:
print("o'clock")
else:
a=m//10
b=m%10
if m<=20:
print(readline[str(m)])
else:
print(readline[str(a)+'0'],readline[str(b)])
clockread(h)
print(' ',end='')
minread(m)
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