1028: [编程入门]自定义函数求一元二次方程

解题思路:

注意事项:

参考代码:

def fun(a, b, c):

    d = b**2 - 4 * a * c

    if d > 0:

        x1 = (-b + pow(d, 0.5)) / (2*a)

        x2 = (-b - pow(d, 0.5)) / (2*a)

        print("x1={:.3f} x2={:.3f}".format(x1, x2))

    elif d == 0:

        x1 = x2 = -b / (2*a)

        print("x1={:.3f} x2={:.3f}".format(x1, x2))

    else:

        x1 = -b / (2*a)

        x2 = pow(-d, 0.5) / (2*a)

        print("x1={:.3f}+{:.3f}i x2={:.3f}-{:.3f}i".format(x1,x2,x1,x2))

def main():

    a, b, c = map(int, input().split())

    fun(a, b, c)

main()