解题思路:
注意事项:
参考代码:#include<iostream>
using namespace std;
int main()
{
double l;
cin >> l;
if (l <= 100000)
{
double l1 = l;
l = l * (1 + 0.1);
cout << l-l1;
}
else if (l <= 200000)
{
double l2 = l;
double n = l - 100000;
l = 100000 * (1 + 0.1) + n * (1 + 0.075);
cout << l-l2;
}
else if (l <= 400000)
{
double l3 = l;
double m = l - 200000;
l = 100000 * (1 + 0.1) + 100000 * (1 + 0.075) + m * (1 + 0.05);
cout << l-l3;
}
else if (l <= 600000)
{
double l4 = l;
double x = l - 400000;
l = 100000 * (1 + 0.1) + 100000 * (1 + 0.075) + 200000 * (1 + 0.05) + x * (1 + 0.03);
cout << l-l4;
}
else if (l <= 1000000)
{
double l5 = l;
double y = l - 600000;
l = 100000 * (1 + 0.1) + 100000 * (1 + 0.075) + 200000 * (1 + 0.05) + 200000* (1 + 0.03)+y*(1+0.015);
cout << l-l5;
}
else
{
double l6 = l;
double z = l - 1000000;
l = 100000 * (1 + 0.1) + 100000 * (1 + 0.075) + 200000 * (1 + 0.05) + 200000 * (1 + 0.03) + 400000* (1 + 0.015)+z*(1+0.01);
cout << l-l6;
}
return 0;
}
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