1141: C语言训练-百钱百鸡问题(python)

解题思路:

注意事项:

参考代码:

price = [5,3,1]
s = 0
cock = 0
hen = 0
chicken = 0
num = 0
for i in range(0,20):
   cock = i
   for j in range(1,33):
       hen = j
       chicken = 100 - (cock + hen)
       if chicken % 3 != 0:
           continue
       s = cock * price[0] + hen * price[1] + chicken // 3 * price[2]
       num = cock + hen + chicken
       if s == 100 and num == 100:
           print("cock={},hen={},chicken={}".format(cock,hen,chicken))