[编程入门]利润计算-题解（C语言代码）

大佬们
我这个为什么不对
https://github.com/islastudio/islastudio.github.io/blob/main/ZiJiXieDeDaiMa/C-LiRunWenTi.c

#include<stdio.h>
int main()
{
    int a, b;
    scanf_s("%d", &a);
    if (a <= 100000)
                b = a *0.1;
    else if (a>100000&&a <= 200000)
                b = 10000 + (a - 100000) *0.075;
    else if (a>200000&&a <= 400000)
                b = 10000 + 7500 + (a - 200000) *0.05;
    else if (a>400000&&a <= 600000)
                b = 10000 + 7500 + 10000 + (a - 400000) *0.03;
    else if (a>600000&&a<=1000000)
                b = 10000 + 7500 + 10000 + 6000 + (a - 600000) *0.015;
    else
            b = 10000 + 7500 + 10000 + 6000 + 6000 + (a - 1000000) *0.01;
    printf("%d\n",

#include<stdio.h>  

int main(void)
{
    int i;
    int a=0;
    int b=0;
    int c=0;
    int d=0;
    int e=0;
    scanf("%d",&i);
    if(i<=100000)
    {
        printf("%d",i*0.1);
    }
    else if(100000<i&&i<=200000)
    {
       
        a=100000*0.1+(i-100000)*0.075;
        printf("%d",a);
    }    
    else if(200000<i&&i<=400000)
    {
        
        b=100000*0.1+100000*0.075+(i-200000)*0.05;
        printf("%d",b);
        
    }
    else if(400000<i&&i<=600000)
    {
      
        c=100000*0.1+100000*0.075+200000*0.05+(i-400000)*0.03;
        printf("%d",c);
    }
    else if

#include <stdio.h>
int main()
{
    double a;
    scanf("%lf",&a);
    printf("%f\n",a<=100000?a*0.1:(a<=200000?10000+(a-100000)*0.075:(a<=400000?10000+7500+(a-200000)*0.05:(a<=600000?10000+7500+10000+(a-400000)*0.03:(a<=1000000?10000+7500+10000+6000+(a-600000)*0.015:17500+16000+6000+(a-1000000)*0.01)))));
    return 0;
}

这个呢，为啥不行？有大佬帮忙看看吗，谢谢

#include <stdio.h>
int main()
{
	int a,s;
	scanf("%d",&a);
	switch(a/100000)
	{
		case 0:
			s=a*0.1;
			break;
		case 1:
			s=100000*0.1+(a-100000)*0.075;
			break;
		case 2:
		case 3:
		    s=100000*0.1+100000*0.075+(a-200000)*0.05;
			break;
		case 4:
		case 5:
		    s=100000*0.1+100000*0.075+200000*0.05+(a-400000)*0.03;
			break;	
		case 6:
		case 7:
		case 8:
		case 9:
			s=100000*0.1+100000*0.075+200000*0.05+400000*0.03+(a-600000)*0.015;
			break;
		default:
		    s=100000*0.1+100000*0.075+200000*0.05+400000*0.03+600000*0.015+(a-1000000)*0.1;	
	}
	printf("%d",s);
	return 0;
}这样好像不彳亍

#include<iostream>
using namespace std;
#define L1 100000*0.1
#define L2 100000*0.1+100000*0.075
#define L3 100000*0.1+100000*0.075+200000*0.05
#define L4 100000*0.1+100000*0.075+200000*0.05+200000*0.03
#define L5 100000*0.1+100000*0.075+200000*0.05+200000*0.03+400000*0.015
int main() {
	int m;
	cin >> m;
	if (m <= 100000)
		cout << (m * 0.1) << endl;
	else if (100000 < m && m <= 200000)
		cout << ((m - 10000) * 0.075 + L1) << endl;
	else if (200000 < m && m <= 400000)
		cout << ((m - 200000) * 0.05 + L2) << endl;
	else if (m > 400000 && m <= 600000)
		cout << ((m - 400000) * 0.03 + L3) << end

#include<stdio.h>
int main(){
	int prize,money;
	scanf("%d",&prize);
	if(prize <= 100000){
		money = prize*0.1;
	} else if(prize <= 200000){
		money = 100000*0.1 + (prize-100000)*0.075;
	} else if(prize <= 400000){
		money = 100000*0.1 + 100000*0.075 + (prize-200000)*0.05; 
	} else if(prize <= 600000){
		money = 100000*0.1 + 100000*0.075 + 200000*0.05 + (prize-400000)*0.03;
	} else if(prize <= 1000000){
		money = 100000*0.1 + 100000*0.075 + 200000*0.05 + 200000*0.03 + (prize-600000)*0.015;
	} else {
		money = 100000*0.1 + 100000*0.075 + 200000*0.05 + 200000*0.03 + 600000*0.015 + (prize-1000000

#include<stdio.h>
int main()
{
	int a,b;
	scanf("%d",&a);
	if(a<=100000)
	{
		b=0.1*a;
		printf("%d",b);
	}
	if(a>100000&&a<=200000)
	{
		b=(a-100000)*0.75+10000;
		printf("%d",b);
	}
	if(a>200000&&a<=400000)
	{
		b=(a-200000)*0.05+17500;
		printf("%d",b);
	}
	if(a>400000&&a<=600000)
	{
		b=(a-400000)*0.03+27500;
		printf("%d",b);
	}
	if(a>600000&&a<=1000000)
	{
		b=(a-600000)*0.015+33500;
		printf("%d",b);
	}
	if(a>1000000)
	{
		b=(a-1000000)*0.01+39500;
		printf("%d",b);
	}
	return 0;
}
救命，为什么不能全对啊？？