方法比较直接（Python）

zfc='qwertyuiopasdfghjklzxcvbnm'
tj=[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,]
while 1:
   t=input()
   if '#' in t:
       break
   for i in list(t):
       if i in zfc:
           tj[ord(i)-ord('a')]=tj[ord(i)-ord('a')]+1
for i in list(t):
   if i in zfc:
       tj[ord(i) - ord('a')] = tj[ord(i) - ord('a')] + 1
for i in range(26):
   print(chr(ord('a')+i),tj[i])