解题思路:吐槽优质题解还是错的,让我检查自己的老半天。
参考代码:
#include int main() { double a[6] = { 0,100000,200000,400000,600000,1000000 }, t[6] = { 0.1,0.075,0.05,0.03,0.015,0.01 },o=0; int n,p; scanf("%d", &p); for (n = 0; p > a[n+1]; n++) { o = o + (a[n + 1] - a[n]) * t[n]; if (n == 4) { n++; break; } } if (p < a[1])printf("%d", (int)(p * t[0])); else printf("%d", (int)(o + (p - a[n]) * t[n])); return 0; }
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