蛇行矩阵-题解(Python代码)

l=[1]
n=int(input())
for t in range(2,n+1):
    for i in range(t,n+1):
        l.append(l[-1]+i)
    print(*l)
    nun=l[1]-1
    l.clear()
    l.append(nun)
print(2*n+1)

2021-11-17 15:07:43 赞 评论