大神的探险 之 破解密码 （C++代码）

解题思路:    

                    范围有点大,所以需要long long

                            

注意事项:

                    狂撸代码就行!

参考代码:

                    #include<iostream>
                    using namespace std;
                    int main()
                    {
                                long long a,b;
                                while(cin>>a>>b)
                                {
                                        if(a==-1&&b==-1)                            //如果都是-1就退出
                                                break;
                                        cout<<a+b<<endl;
                                }
                                return 0;
                    }