C语言程序设计教程（第三版）课后习题10.4 （C语言,for循环,简单快捷）

解题思路:
                先接受一个字符保存字符位数,然后读取输入位数,最后读取要截取长度的位置

                这里分成三个部分:

                                      1:读取输入,分别读取输入长度和长度位数和截取的位置,用三个数据保存

                                      由于想要截取输出的长度为m-n,然后再输出输入的位数

                                       所以需要输出的长度为n,即用数组输出,需要输出的n为当前数组长度

                                       2:输出当前数组长度n,输入的数组下标为输出的数组下标m

                                       3:按照原式输出数组,用for循环当成每一位输出,输出的下标为m-n;
注意事项:
                楼主这里是把m,n写成了a和b,其实是一样的
参考代码:

                            #include<stdio.h>
                            int main(void)
                            {
                                     int str[100],a,b,c;                            //设置变量数组str,a,b,c
                                     scanf("%d",&a);                            //读取m长度
                                     for(int i=0;i<a;i++)                        //读取m个数
                                          scanf("%d",&str[i]);
                                     scanf("%d",&b);                            //读取想要截取的n
                                     c=a-b;                                           //m-n个数
                                     for(int i=c;i<a;i++)                         //输出截取的位置, 且下标为m                                  

                                           printf("%d ",str[i]);                    
                                     for(int i=0;i<c;i++)                        //依次输出m-n个数;
                                          printf("%d ",str[i]);
                                    return 0;
                          }

                          //由于是输入的是整数而不是字符,所以不用理会输入换行所占用得字符长度