解题思路:
画图形 找规律
注意事项:
参考代码:
import java.util.Scanner;
public class Main
{
/*
* 平面上有两个矩形,它们的边平行于直角坐标系的X轴或Y轴。对于每个矩形, 我们给出它的一对相对顶点的坐标,请你编程算出两个矩形的交的面积。
*/
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
double[][] arr = new double[2][4];
for (int i = 0; i < 2; i++)
{
for (int j = 0; j < 4; j++)
{
arr[i][j] = input.nextDouble();
}
}
double x1 = min(max(arr[0][0], arr[0][2]), max(arr[1][0], arr[1][2]));
double x2 = max(min(arr[0][0], arr[0][2]), min(arr[1][0], arr[1][2]));
double y1 = min(max(arr[0][1], arr[0][3]), max(arr[1][1], arr[1][3]));
double y2 = max(min(arr[0][1], arr[0][3]), min(arr[1][1], arr[1][3]));
double width = x1 - x2;
double length = y1 - y2;
double s = width * length;
if (width > 0 && length > 0)
{
System.out.printf("%.2f", s);
} else
{
System.out.println("0.00");
}
}
public static double max(double a, double b)
{
return ((a > b) ? a : b);
}
public static double min(double a, double b)
{
return ((a < b) ? a : b);
}
}
0.0分
3 人评分