Manchester- C语言训练-角谷猜想

何必呢，输入1循环了两次就出来了，多此一举吗不是

何必呢，输入的是1，循环两次出来不还是1，多此一举吗不是

#include<stdio.h>
int jiaogu(int n){
	if (n==1) return 0;
	if (n%2==0) {
		printf("%d/2=%d\n",n,n/2);
		return jiaogu(n/2);
		}
	else {
		printf("%d*3+1=%d\n",n,(n*3+1));
		return jiaogu(n*3+1);
		}	
	}
 
int main(void){
	int n;
	scanf("%d",&n);
	jiaogu(n);
	return 0;
	}

#include <stdio.h>
int main()
{
	int a;
	scanf("%d",&a);
	while(a!=1)
	{
		int i,j;
		if(a%2==0)
		{
			i=a/2;
			printf("%d/2=%d\n",a,i);
			a/=2;
		}else
		{
			j=a*3+1;
			printf("%d*3+1=%d\n",a,j);
			a=a*3+1;
     	}
	}
	return 0;
}

#include<stdio.h>
#pragma warning(disable:4996)
int main()
{
	int a;
	scanf("%d", &a);
	e:
	while (a != 1)
	{
		if (a % 2 == 0)
		{
			printf("%d/2=%d\n", a, a / 2);
			a /= 2;
			goto e;
		}
		else(a % 2 == 1);
		{
			printf("%d*3+1=%d\n", a, a * 3 + 1);
			a = a * 3 + 1;
			goto e;
		}
	}
	return 0;
}

#include<stdio.h>
int main()
{
	int n=0;
	scanf("%d",&n);
	while(n!=1){
		if(n%2==0){
			printf("%d/2=",n);
			n=n/2;
			printf("%d\n",n);
		}
		else{printf("%d*3+1=",n);
		n=n*3+1;
		printf("%d\n",n);
		}
	}
	return 0;
}

这小于小于什么鬼？