统计满足条件的4位数个数

解题思路:

注意事项:

参考代码:

n = int(input())

l = list(map(int,input().split()))

count = 0

for i in l:

    a = i%10

    b = int(i/10) % 10

    c = int(i/100) % 10

    d = int(i/1000) % 10

    if a - (b+c+d) > 0:

        count = count + 1

print(count)