1049: [编程入门]结构体之时间设计

解题思路:

注意事项:

参考代码:

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

struct tim

{

    ll n;

    ll y;

    ll r;

};

int main()

{

    tim t1;

    ll sum=0;

    ll yue[129]={0,31,28,31,30,31,30,31,31,30,31,30,31};//多开点，把0让出来

    cin>>t1.n;

    cin>>t1.y;

    cin>>t1.r;

    if(t1.n%4==0&&t1.n%100!=0||t1.n%400==0)

    {

        yue[2]=29;//变成2月

    }

    for(int i=1;i<=t1.y-1;i++)

    {

        sum+=yue[i];

    }

    sum+=t1.r;

    cout<<sum;

    return 0;

}