2936: 简单算术表达式求值

解题思路:

注意事项:

参考代码:

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

ll jiafa (ll x,ll y,char z)

{

    if(z=='+')

    {

        return x+y;

    }

}

ll jianfa (ll x,ll y,char z)

{

    if(z=='-')

    {

        return x-y;

    }

}

ll chengfa (ll x,ll y,char z)

{

    if(z=='*')

    {

        return x*y;

    }

}

ll chufa (ll x,ll y,char z)

{

    if(z=='/')

    {

        return x/y;

    }

}

ll quyu (ll x,ll y,char z)

{

    if(z=='%')

    {

        return x%y;

    }

}

int main()

{

    int a,b;

    char c;

    cin>>a>>c>>b;

    if(c=='+')

    {

        cout<<jiafa(a,b,c);

    }

    if(c=='-')

    {

        cout<<jianfa(a,b,c);

    }

    if(c=='*')

    {

        cout<<chengfa(a,b,c);

    }

    if(c=='/')

    {

        cout<<chufa(a,b,c);

    }

    if(c=='%')

    {

        cout<<quyu(a,b,c);

    }

    return 0;

}