解题思路:
注意事项:
参考代码:
#include <stdio.h> int main(void) { int n, sum = 0; scanf("%d", &n); if(n <= 100000) { sum += n*0.1; } if(100000 < n && n <= 200000) { sum += (n-100000)*0.075; } if(200000 < n && n <= 400000) { sum += (n-200000)*0.05; } if(400000 < n && n <= 600000) { sum += (n-400000)*0.03; } if(600000 < n && n <= 1000000) { sum += (n-600000)*0.015; } if(n > 1000000) { sum += (n-1000000)*0.01; } printf("%d\n", sum); return 0; }
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