利用求根公式球一元二次方程的解

解题思路:

            求根公式:  x1=(-b-sqrt(b^2-4ac))/2a

                            x2=(-b+sqrt(b^2-4ac))/2a

注意事项:
            a!=0
参考代码:

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);

while (scanner.hasNext()) {

double a = scanner.nextDouble();

double b = scanner.nextDouble();

double c = scanner.nextDouble();

double x1 = (-b-Math.sqrt(b*b-4*a*c))/2*a;

double x2 = (-b+Math.sqrt(b*b-4*a*c))/2*a;

if(x1>=x2){

    System.out.printf("%.2f %.2f",x1,x2);

}

else{

    System.out.printf("%.2f %.2f",x2,x1);

}

}

}

}