【C语言题解】题目 1010: [编程入门]利润计算

解题思路:
分别计算每一部分的利润，逐次累加
注意事项:

参考代码:

#include<stdio.h>

int main(){

    long int a,profit,t;

    scanf ("%ld",&a);

    //t存储a的数值

    t=a;

    //超出100000的部分不计算

    if (a>100000)

        a=100000;

    profit=a*0.1;

    //得到剩下没有计算的奖金赋值给a，如果a>0继续计算。

    a=t-100000;

    if (a>0){

        重复进行上面的运算

        t=a;

        if (a>100000)

            a=100000;

        profit+=a*0.075;

        a=t-100000;

        if (a>0){

            t=a;

            if (a>200000)

                a=200000;

            profit+=a*0.05;

            a=t-200000;

            if (a>0){

                t=a;

                if (a>200000)

                    a=200000;

                profit+=a*0.03;

                a=t-200000;

                if (a>0){

                    t=a;

                    if (a>400000)

                        a=400000;

                    profit+=a*0.015;

                    a=t-400000;

                    if (a>0){

                        profit+=a*0.01;

                    }

                }

            }

        }

    }

    printf("%d",profit);

    return 0;

}